Thursday, October 27, 2011

Thursday, October 27th

Sixth Grade

Do your best to answer the rest of the questions on the Cartoon Corner! We won't have math class tomorrow, so you have until Monday.

Seventh Grade

Math - Finding a discount. Remember, to find a discount, take the percent and first move the decimal two places to the left. (So, 15% becomes 0.15 ; 25% becomes 0.25 ; 40% becomes 0.4) Then, multiply that decimal by the dollar amount. Remember to move the decimal number over enough places. This amount is your discount. If you get an amount that doesn't look like money because it has too many decimal places, round to the second decimal place. For example, if you have multiplied the dollar amount and the decimal and you get something like 5.275, you would need to round to the second place. The 7 is in the second place, so you look at the 5. 5 makes the 7 go up 1 to 8. Now you have 5.28 and that can be written as money, $5.28. Once you have your discount, you can find the amount you pay by subtracting the discount from the original amount.

Geography - Finish reading Chapter 7, Section 2 and answer the assessment questions #1-4.
Align Center
Eighth Grade

Pre-Algebra: Graph the 15 equations. Remember, an equation that only contains one variable will be either vertical or horizontal. If it a y equals equation, then it is a horizontal line and crosses the y-axis at the the number. So, y = -3 would be a horizontal line on -3 on the y-axis. For x = -2, that would be a vertical line, crossing the x-axis at -2.

Algebra I: Parallel and Perpendicular lines: Parallel lines have the same slope, so if you need to write an equation of a line that is parallel to another line, all you need from the other line is the slope. It will be the same. Sometimes, you can make up the y-intercept, but on others, you will have to find the y-intercept because it will tell you that your new line goes through a given point. Here is an example:

Write the equation of a line that is parallel to the given line and passes through the given point:

y = -2x + 4 ; (-2, 3)

Since it is parallel to the line, y = -2x + 4, you know it will have the same slope. The slope is -2. You don't know the y-intercept of the new line, but you do know a point the new line will go through. Use the slope and the coordinates of the point to solve for the y - intercept:

y = -2x + b

3 = -2 times -2 + b

3 = 4 + b

-1 = b

Now that you've solved for the y-intercept, you can plug that into the equation:

y = -2x -1

To write equations for perpendicular lines, you will do the same process. Just remember that the slope has to be the opposite reciprocal of the given line's slope.

EMAIL ME IF YOU HAVE QUESTIONS! You WILL have class tomorrow!

See you then,

Mrs. Swickey