Sixth Grade
Lesson 28. Be sure to use your manipulatives! If the question is asking for 1/3 of 3/5's. Put 3 of your 1/5 pieces together. To find 1/3 of something you would divide it by 3, so to find 1/3 of 3/5's, divide your pieces into 3. That means 1/3 of 3/5 is just 1/5!
Seventh Grade
We continued working on ITBS tests today. There is just one test left, so we will be back to working on curriculum tomorrow! Don't forget to work on your Spelling unit and Vocabulary.
Eighth Grade
Lesson 2-4. Estimating square roots. Remember to use the square root tables at the back of your sourcebook. If you didn't take the sourcebook home, click on the link in yesterday's post. (just scroll back to look)
For the first section, you are finding the two integers that a square root is between. If you need to know what two integers the square root of 39 is between, think about what perfect squares are close to the number 39. 6x6=36 and 7x7=49, so the number 39 is between the two perfect squares of 36 and 49. That means that the square root of 39 is between the integers 6 and 7. Remember, an integer does not have a decimal. It is only the whole numbers and their opposites (negative numbers)
For the second section, you are estimating the square roots to the nearest TENTH (not hundredth). To do this, think about what two integers a square root is between - like what you were doing for the first section - then take a logical guess to the nearest tenth. To use the example from above, 39 is between 6 and 7, and since 39 is closer to 36 than to 49, a good guess might be 6.3. To test it, multiply 6.3 x 6.3 ( you cannot use a calculator - you MUST show the multiplication on your paper to do this part!). 6.3 x 6.3 = 39.69. That is just a little over 39. To test 6.2 x 6.2 to see if it is closer, multiply it too. That equals 38.44 which is closer by just a bit. So, the answer would be 6.2. (NOT 38.44)
On the back page, you continue doing the same thing as in the second section. Then, for the number line, you will also do the same thing, but then find the letter that is closest to your estimate. So, if there was a letter a little to the right of the 6 on the number line, then that is what you'd put for the square root of 39.
For the last section. you are estimating to the nearest HUNDREDTH (following the directions) using a calculator. To do this, first look at the problem. Are either one of the square roots to be multiplied a perfect square? If so, simplify it. For example, if you were to multply the following:
Since 49 is a perfect square, you would put into your calculator in this order - 35, square root sign, x 7 =. That would give you the answer. Round it to the nearest hundredth. You would get 41.41.
Don't forget to do ALL of the spiral review! The assignment is:
#2-36 evens and #40-44 ALL.
See you tomorrow!
Mrs. Swickey
p.s. Sorry this is later than usual. I got home late!